| User Area > AdviceEquivalent force distributionIn the finite element method, the
        equilibrium equation {f}=[K]{d} is solved for displacements {d} at the nodal locations.
        Hence, both the applied forces {f} and the stiffness {K} are required at these nodal
        positions. For example, the assignment of a constant body force (force per unit volume)
        requires that a transformation be performed from the volume-based loading to a set of
        equivalent concentrated loads that are then applied to the nodes  hence the force
        vector is commonly termed the equivalent nodal load vector. Such force vectors are also termed
        consistent because the same assumptions (shape functions, integration order
        etc.) are used as in the generation of the stiffness matrix. That is, the stiffness and
        the force are consistent with each other. The only exceptions to this are the continuum
        solid elements and section 5.1 of the theory manual (General Load Types)
        should be consulted for further information This section describes the way in which the
        finite element assumptions are used to convert a force on an element into equivalent nodal
        loading, specifically, the application of a uniformly distributed load to a 3-noded bar
        element. The equivalent nodal force load {r} for
        such a uniformly distributed loading {p} is given by   Where [N] are the shape functions and S is
        the area over which the uniformly distributed load integration is to be performed. In the case of a 3-noded bar element, the
        axial distributed load {p} is applied as follows   and in vector form as 
 If t
        is the width of the bar and dx, an incremental
        length along the bar, then the incremental surface area is   Given   So that    Therefore, 
                      changing the integration limits from the local to the natural 
                      coordinate system, the equivalent nodal force is given 
                      by   Using the quadratic shape function for this bar element   This integral 
                      is accurately evaluated using a two-point Gauss 
                      integration rule in which the weight is 1 and the optimum 
                      sampling points are  . 
                      So that   Or finally   Thus a constant, uniformly distributed load
        applied along the length of a 3-noded bar element is transformed into equivalent nodal
        loads which are distributed according to the ratio  .
        If the equivalent nodal forces (px1*tL),
        (px2*tL) and (px3*tL) are denoted by the constant f, then,
        diagrammatically this distribution becomes   The same distribution is obtained for
        uniformly distributed edge loading on an 8-noded, 2D plane element of side length (L) and
        thickness (t), as follows 
 A constant, uniformly distributed load {p}
        applied to the surface of an 8-noded surface element can be similarly examined to observe
        the ratio of the corner and midside nodes to be  ,
        diagrammatically shown as follows 
 In this case, f = A*p,
         where (A) is the surface area of the
        element. Because the element stiffness and forces
        are consistent with each other, this apparently incorrect distribution is
        actually entirely valid and, indeed, essential. A number of implications arise from the use
        of the equivalent load vector in finite element analyses and are considered below. Implication:  Equivalent Loading Across Multiple Elements The foregoing discussion has been
        based on a higher order element. The use of lower order elements does not produce such an
        anomaly and the load is distributed equally between the nodes of the element. When elements are combined in a mesh
        and loading applied across multiple higher order elements the same distribution takes
        place. It is worth noting, however, that the nodes common to the adjoining elements
        receive a force contribution from each of these elements. As an example, consider the
        diagram below in which two, higher order elements are subject to a constant, uniformly
        distributed load (p), as before. 
 In this case the centre node receives an
        equivalent force contribution from the two adjoining elements of (2f*1/6)). The same is true for a linear element assemblage
        as follows   If a summation of element reactions is
        performed over a single element then this additional contribution from the adjacent
        element(s) would need to be subtracted to be absolutely correct. Implication:  Loading Attribute Visualisation Arrows In Reverse
        Directions With a model load case active, select the
        attribute properties and then the loading tab. Press the button marked
        settings
, where the following two options will be seen 
                 Show discrete loading by
        definition Show discrete loading by
        effect on mesh By default the latter is invoked and will
        show the equivalent nodal forces as described above, whilst the former will visualise the
        forces as defined in the attribute definition without any additional transformation into
        equivalent loads. This explains why visualising the loading attributes on a mesh, can
        produce a series of arrows that either alternate unexpectedly in size or reverse in
        direction. Discrete loads are not the only loading
        types that are processed in this way for higher order elements; it applies equally to
        practically all loading types. Implication:  Planar Displacement Fields Applying Concentrated Loads to
        the edge of a higher order element to produce a uniform and planar displacement of all the
        nodes on that edge requires that the concentrated loads be applied in the ratios given
        above. The Global Distributed loading
        also applies concentrated loads directly to the nodes in the same way that selecting the
        Concentrated load tab would, however, in the former case, the element shape
        functions are accounted for and the distribution handled automatically. All other loads in LUSAS are also handled
        automatically. Implication:  Reactions Are Unexpectedly Not Constant Along A
        Supported Boundary Support reactions are also distributed
        according to the same principles. Hence the constant nodal reactions that would be
        naturally expected from the application of a uniformly distributed load would actually be
        distributed in the ratios given above. The sum of the reactions over a single
        element, however, will accurately represent the total reaction acting over the length/area
        of the element. Implication:  Equivalent Nodal Loading For Beam/Shell/Plate
        Elements This equivalent nodal load transformation
        (or decomposition) must produce kinematically equivalent nodal forces from the applied
        element loads for elements that support moment output. For such elements, this will mean
        that a constant uniformly distributed load over the length of the element will produce
        both an equivalent shear force and a bending moment. Kinematically equivalent loads are so named because they replace
        a distributed load so that the correct work is maintained. To replace the distributed load
        by statically equivalent forces would be
        incorrect and could result in errors when solving for the displacements  especially
        in coarse mesh definitions. In MODELLER, kinematically equivalent loads
        are calculated for the relevant elements automatically. For example, a constant value of uniformly
        distributed load (P) on a single beam element of length L has a kinematically equivalent
        nodal load defined as follows   Whereas, the statically equivalent load is
        defined as follows   It is for this reason that visualisation of
        loads in MODELLER can display additional moments at nodes on which a uniformly distributed
        load has been applied. Discrete loading is an important exception
        to this general rule of decomposition. Discrete loading is applied to the finite element
        mesh and is converted into equivalent nodal loads using the shape functions of the
        elements. These nodal loads are then applied directly to the underlying structural mesh.
        Although these nodal loads correctly represent the vertical and in-plane components of the
        applied loading, they do not account for any kinematic decomposition. The effect of this
        is mesh dependent and, in the general case, is not an issue. For very coarse meshes this
        assumption may cause the results to be affected.  Implication:  Joining Lower And Higher Order Elements  It is tempting on occasion to try to
        join lower and higher order elements together, typically when attempting to generate a
        mesh transition from higher order elements to low order element. For instance, consider
        transitioning from 4-noded to 8-noded quadrilateral elements as follows 
 To demonstrate the effect of mixing
        elements in such a manner, consider the above situation in which a prescribed displacement
        of unity is applied to one end of the structure with support conditions as follows 
  This loading is expected to produce a
        planar response throughout the structure as shown in the top-most diagram (below) where
        two 8-noded quadrilaterals are used. The lower of these two diagrams is the response when
        mixing the element types. Both diagrams show the nodal displacement magnitudes in the
        X-direction.   The reason for the non-planar displacement
        field obtained may be seen by considering the equivalent nodal force distributions
        required for both the 4-noded and 8-noded elements to transmit such a planar force. The
        following diagram shows the distributions at the element interface   For the expected results to be obtained the
        distribution needs to be identical. If the difference in the distribution ratios is
        considered we have   Although the total force across the
        interface will be correct, the distribution of the force will not be. That is, the
        difference in the ratio at nodes 1 and 4 produce a net difference in the loading of f/12,
        whereas nodes 2 and 5 produce a net difference of f/6 in the opposite direction. The
        direction of these force ratio differences correlate with the non-planar displacements
        that are seen, that is nodes 1 and 4 displace in the same direction as the net f/12 force
        and nodes 2 and 5 displace according to the direction of the f/6 net force. If it is necessary to join elements in such a manner, it is
        recommended that constraint equations be used to ensure that the nodes along the element
        interface are constrained to displace in a planar manner.  In summary, the joining of low and
        high order elements in such a manner is a dubious practice, to be avoided if at all
        possible and is discouraged on the basis of the different nodal force distribution (as
        well as stiffness) associated with the different element types which may cause inaccuracy
        in the results. Together with this inaccuracy the possibility of exciting an element mechanism in the 8-noded element when reduced
        integration is being used is greatly increased. 
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